Calculate the standard change in Gibbs free energy for the following reaction at

Question

Calculate the standard change in Gibbs free energy for the following reaction at 25 °C. Use the G°f values found in the Chempendix.

The answer is not -70.7, 70.7, 171.37, -171.37, -66.3

Map out Sapling Learning Calculate the standard change in Gibbs free energy for the following reaction at 25 . Use the as-values found in the Chempendix Number k.J/ mol There is a hint available! View the hint by clicking on the divider bar again to hide the hint. Close Previous 8 Give Up & View Solution O Check Answer ) Next Exit Hint

Explanation / Answer

we have:

Gof(NO2(g)) = 51.31 KJ/mol

Gof(H2O(l)) = -237.129 KJ/mol

Gof(HNO3(l)) = -80.71 KJ/mol

Gof(NO(g)) = 86.55 KJ/mol

we have the Balanced chemical equation as:

3 NO2(g) + H2O(l) ---> 2 HNO3(l) + NO(g)

deltaGo rxn = 2*Gof(HNO3(l)) + 1*Gof(NO(g)) - 3*Gof( NO2(g)) - 1*Gof(H2O(l))

deltaGo rxn = 2*(-80.71) + 1*(86.55) - 3*(51.31) - 1*(-237.129)

deltaGo rxn = 8.329 KJ/mol

Answer: 8.329 KJ/mol

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.