A spring stretched a distance s is said to have potential energy Us= 1/2 ks^2. S
ID: 1910488 • Letter: A
Question
A spring stretched a distance s is said to have potential energy Us= 1/2 ks^2. Since the force required to stretch the spring a distance s is k s, by Hooke's law, why isn't the potential energy ks^2 (force times distance)? A. The potential energy is actually zero, but to have something to work with that depends on s we say it's 1/2 ks^2 B. The 1/2 is just a matter of definition and could be left out C. All of these, except sometimes D. The spring pulls back as we stretch it out, so we do only part of the work we would do if it didn't pull back E. None of these F. The force is not constantExplanation / Answer
F) The force is not constant
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