In the figure, a lead brick rests horizontally on cylinders A and B. The areas o

Question

In the figure, a lead brick rests horizontally on cylinders A and B. The areas of the top faces of the cylinders are related by A 2.8 A the Young's moduli of the cylinders are related by EA 1.6 Ee. The cylinders had identical lengths before the brick was placed on them. What fraction of the brick's mass is supported (a) by cylinder A and (b) by cylinder B? The horizontal distances between the center of mass of the brick and the centerlines of the cylinders are dAfor cylinder A and defor cylinder B. (c) What is the ratio dA/de? com of brick

Explanation / Answer

Fa/(AaEa)=Fb/(AbEb)
A= area
F = force of the brick supported
Fa/Fb=4.48
(s)so fraction supprted by A = 4.48/5.48 = 0.8175
(b)fraction supported by B = 1-0.8175 = 0.1825
(c) conserving moment about centre of gravity of the brick => Fada=Fbdb
gives da/db=0.2242

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