A rectangular coil with resistance 200ohms has 50turns, each length L=10cm and w

Question

A rectangular coil with resistance 200ohms has 50turns, each length L=10cm and width w=5cm. The coil moves in a uniform magnetic field of B=1.2T with constant velocity=10m/s. 1.Calculate the induced emf when the right edge is about to enter the field. 2.Calculate the induced emf when the left edge is about to enter the field. 3. .Calculate the induced emf when the when the coil moves from being just totally inside the field to (on the left side) until its just about to emerge from the field on the right. 4. Calculate the force on each of the edges of the coil. 5.While the coil is penetrating the field and while it is totally inside the field. 6.Now the coil is lying motionless and flat on the field, and it is rotated about in a axis through the right side of the coil, such that the left sides rises, leaving the coil perpendicular to the field. This is done in 0.1second. What is the average emf induced in the coil and what is the average induced current.

Explanation / Answer

1. induced emf = NlvB is the formula. solve first three bits using this formula.

2. force on the loop is given by F = ilB     for 4 bit.

3. torque = X B

4. induced current i = /R

iam sory for not solving as it is too many bits, i dont want points, check whether those formulas may be useful

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