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When a gas follows path 123 on the PV diagram in Figure P12.46, 415 J of heat fl

ID: 1916681 • Letter: W

Question

When a gas follows path 123 on the PV diagram in Figure P12.46, 415 J of heat flows into the system, and 167 J of work is done. http://www.webassign.net/sf5/p12_46.gif (a) What is the change in the internal energy of the system? J (b) How much heat flows into the system if the process follows path 143? The work done by the gas along this path is 63.0 J. J What net work would be done on or by the system if the system followed (c) path 12341? J (d) path 14321? J (e) What is the change in internal energy of the system in the processes described in parts (c) and (d)?

Explanation / Answer

418 J of energy flows into the system by heat and -167 J of work is done on the gas. a.) what is the change in the internal energy of the system? For path 123 Change inInternall energy = 418 - 167 = 251 J [The terminology used in question is not proper. either work done (by) or (on) OR "+" , "-" signs should be used with only "by". both by on and + _ should not be used it creates confusion. Because diagram was given I could know that work has be done by gas b.) how much energy Q flows in the system if the gas follows path 143? The work done on the gas along this path is -63.0 J. Energy flow (as heat) into the system for path 143 = 251 - 61 = 188J [Data on work done by gas in a) and b) does not match the indicator diagram. These values must be identical. Comment on language same as in a)] c.) What net work would be done on OR by the system if the system followed path 12341. As per the figure it work donr by or on gas should be zero. As per data. Net work is done by gas = 167 - 63 =104 J d.) and path 14321. As per the figure it work done by or on gas should be zero. As per data. Net work is done by gas = 63 -167 = - 104 J or it should be writen s wok done on gas is 104 J e.) what is the change in internal energy of the system in the processes described in parts C and D? Change in inetnal energy for c) - 12341 path and d) -14321 path = zero

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