Chapter 3: Mendelian Genetics&Probability; 32. If Titall) is donsinant over t (s

Question

Chapter 3: Mendelian Genetics&Probability; 32. If Titall) is donsinant over t (short), then what proportion of the progeny from the cross TtTT will be ta A) 0/4 8) 1/4 C) 2/4 D) 3/4 E) 4/4 33. If there is a 1/4 probability of having a green seed and a 1/3 probability of having a then what is the probability that progeny will have seeds that are 80TH green AND rour round seed from a genetic cross B) 1/4 C) 2/7 D) 1/12 E) 7/12 34. If there is a 1/3 probability of having a green seed and a 1/2 probablity of probability that the progeny will have seeds that are EITHER green having a round seed, then what is the OR round? A) 1/2 B) 1/3 C) 1/6 D) 5/6 E) 7/6 35. If T (tall) is dominant to t (short), and a tall individual (of unknown genotype) produces short cross, what must the genotype of the tall individual be? offspring in a test C) D) tt It cannot be determined a monohybrid cross between two individuals that are both heterorygous for the alleles of a single given trait, and ele is completely dominant over the other, the phenotypic ratios in the progeny (offspring) is always A) 1 dominant :1 recessive B) 2 dominant :1 recessive C) 3 dominant :1 recessive D) 3 recessive : 1 dominant erorygous for the alleles of a single given trait n a monohybrid cross between two individuals, both het where one allele is completely dominant over the other, the genenetrat in the progeny (offspring) is always: A) 1 AA:1 oa B)1AA:1Aa: 1aa C)2 AA:1 oo D) 1 AA:2 Aa:1 aa E) none of the above

Explanation / Answer

32.
Option E is correct.
Parental cross: Tt X TT
Progeny = TT Tt
None of them are short.
All of them are tall.

33.
Option D is correct.
Total probability = 1/3 X 1/4 = 1/12

34.
Option B is correct.
Total probability = 2/3 X 1/2 = 1/3

35.
Option B is correct.
The person must carry t allele for him to produce short progeny in the next generation. So, he must be heterozygous.

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