A cannon is fired horizontally from atop a 40.0 m tower. The cannonball travels
ID: 1952868 • Letter: A
Question
A cannon is fired horizontally from atop a 40.0 m tower. The cannonball travels 145 m horizontally before it strikes that ground. With what velocity did the ball leave the muzzle?_______________ m/s
Your projectile launching system is partially jammed. It can only launch objects with an initial vertical velocity of 42.0 m/s, though the horizontal component of the velocity can vary. You need your projectile to land 211 m from it launch point. What horizontal velocity do you need to program into the system?
_____________ m/s
Explanation / Answer
A cannon is fired horizontally from atop a 40.0 m tower. The cannonball travels 145 m horizontally before it strikes that ground. With what velocity did the ball leave the muzzle?
_______________ m/s
H=.5at^2
40 = .5(9.8)t^2
t=2.857 sec
d=vt
145 = 2.857v
v= 50.75 m/s
Your projectile launching system is partially jammed. It can only launch objects with an initial vertical velocity of 42.0 m/s, though the horizontal component of the velocity can vary. You need your projectile to land 211 m from it launch point. What horizontal velocity do you need to program into the system?
_____________ m/s
initial vertical velocity=42 m/s
vertical acceleration=g=9.8 m/s2
let the projectile took t s to travel 211 m horizontally
let horizontal velocity=v
horizontal acceleration=0
211=v*t
t=211/v
vertical displacement=0
time=t
h=u*t-(1/2)*g*t2
0=42*(211/v)-(1/2)*9.8*(211/v)2
8862/v=218152.9/v2
8862*v=218152.9
v=24.62 m/s
horizontal velocity should be 24.62 m/s
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