Compute the mass of a 6.5 ft by 2.0 ft by 1.0 ft bathtub of water. 70% of the vo

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Explanation / Answer

First, compute the total volume of the bathtub, thatd be V=6.5*2.0*1.0 --> V=13ft^3 Then you know that 70% of that volume is filled with copper and the other 30% with water. So the volume of copper would be 0.7*V = Vc = 9.1ft^3 And the volume of water would be 0.3*V = Vw = 3.9ft^3 Knowing the densities, Coppers density= 559 lb/ft^3 and waters density= 62 lb/ft^3 With the equation Density=mass/volume Then Mass= Density*Volume Water Mass= (62 lb/ft^3)*(3.9 ft^3)=241.8 lb Copper Mass= (559 lb/ft^3)*(9.1 ft^3)=5086.9 lb Then the total mass of the bathtub would be the sum of the copper mass + water mass ==> Total mass= 241.8+5086.9 = 5328.7 lb

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