<p>A dog runs around in the horizontal. Her velocity is given by v = (At2 &#8211

Question

<p>A dog runs around in the horizontal. Her velocity is given by v = (At2 &#8211; B) i + (Ct) j,<br /><br />where i and j are unit vectors in the east and north directions, respectively.<br /><br />A) If the dog is running due north at 3.00 m/s at t = 6.00 seconds, determine &#8216;C&#8217;<br /><br />B) The dog accelerates at (-2.00 m/s2) x + (0.50 m/s2) y at t = 4.00 seconds. Determine the coefficients &#8216;A&#8217; and &#8216;B&#8217;.</p>

Explanation / Answer

v = At2+B i + Ct j a) at t=6 sec v= 3j m/s so 3= C* 6 c= 0.5 m/s2 b) a = dv/dt = 2At i + Cj at t= 4 sec ax = 8A = -2 so A= -0.25 there is no further imformation given to find B

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