<p>A diver observes a bubble of air rising from the bottom of a lake, where the

Question

<p>A diver observes a bubble of air rising from the bottom of a lake, where the pressure is 4.00 atm, to the surface, where the pressure is 1.00atm. The temperature at the bottom of the lake is 5.0 degrees C, and the temperature at the surface is 29.0 degrees C. What is the ratio of the volume of the bubble as it reaches the surface to its volume at the bottom?</p>
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Explanation / Answer

Use the ideal gas law, PV = nRT. n and R are both constants in this case (n is constant because the number of atoms in the bubble isnt changing and R is just a number), so PV/T is a conserved quantity, ie P1V1/T1 = P2V2/T2, so V2/V1 = (P1/P2)(T2/T1) = (4atm/1atm)(29 C/5 C) = 23.2 So the bubble at the surface is 23.2 times larger in volume than the bubble at the bottom of the lake.

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