A simple elevator ride can teach you quite a bit about the normal force as this

Question

A simple elevator ride can teach you quite a bit about the normal force as this rider below can (hopefully) toll you. There are three deferent scenarios given detailing the riders experience m an unnamed hotel For each scenario, calculate the normal force acting on the rider if his mass s m = 78. 1 kg and the acceleration due to gravity 9 = 9. 81 m/s?. In scenario1. the elevator has constant velocity. In scenario 2 the elevator is moving with upward acceleration a2 = 4 84 m's2. Finally, in scenario 3. unfortunately for the rider, the cable breaks and the elevator accelerates downward at a3 = 9. 81 m/s2.

Explanation / Answer

Forces on the person are F normal and mg Acceleration of the person a =net force / mass a = (mg - F N) /m, in in downward direction So, F N = m(g-a) In case 1, a= 0 so, F N,1 = mg = 78.1*9.81 =766.161 N In case 2, a = -4.84 m/s^2 F N,2 = 78.1(9.81 +4.84) = 1144.165 n In case 3, a = g So, F N,3 = 0

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