In an old-fashioned amusement park ride, passengers stand inside a 4.6m--diamete

Question

In an old-fashioned amusement park ride, passengers stand inside a 4.6m--diameter hollow steel cylinder with their backs against the wall. The cylinder begins to rotate about a vertical axis. Then the floor on which the passengers are standing suddenly drops away! If all goes well, the passengers will "stick" to the wall and not slide. Clothing has a static coefficient of friction against steel in the range 0.65 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. A sign next to the entrance says "No children under 30kg allowed."


What is the minimum angular speed, in , for which the ride is safe?

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Explanation / Answer

for minimum speed when the floor may be removed the friction is thelimiting force which is equal to µsN so µsN=mg but N=mv*v/r so µs*mv*v/r=mg hence v=vrg/µs so angular velocity=?=v/r angular frequency=?/2p=rotational frequency in rpm the value is (above found value)*60=

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