Consider a long, plastic cylinder of length L and radius R . The cylinder is cha

Question

Consider a long, plastic cylinder of length L and radius R . The cylinder is charged uniformly, with charge density p (roh) . Now take a power drill and excavate a cylindrical hole (length l , radius a ) out of the cylinder. The axis of the hole should be parallel to the axis of the original cylinder and a distance d away from it, as shown in the diagram above. QUESTION: Referring to the diagram, what is the electric potential of point Q relative to point O? [Hint: consider OP and PQ seperately.]

Explanation / Answer

The potential difference between O and Q can be represented as V_OQ = V_OP - V_PQ Point O and P lie inside the bigger cylinder with charge density rho. Potential at point P is k*rho*pi*(d-a)^2*L/(d-a) which is also the potential difference between the points O and P potential as point Q is calculated with respect to the cylinder of density -rho V_PQ = k*-rho*pi*(a)^2*L/(a) therefore potential difference = k*rho*pi*(d-2a)*L

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.