A baseball of mass m = 0.145 kg is dropped from the top of a tall building 302.0

Question

A baseball of mass m = 0.145 kg is dropped from the top of a tall building 302.0 m above street level. The baseball
lands on the center of a trampoline whose surface (when
at and at rest) is 2.00 m above street level. The trampoline
can be treated as a spring with spring constant k = 150.0 N/m, where the displacement of the center of the trampoline
corresponds to the displacement x of the spring. The coefficient of air resistance for the baseball is a = 1:30 x 10^-3 N s^2/m^2.

(c) Assuming that the baseball reaches the terminal velocity before it hits the trampoline, what is
the work done by the force of air resistance between the release of the baseball from the top of the building and
the impact of the ball on the surface of the trampoline?

Explanation / Answer

drag force=cd*vt^2 where cd=coeff of air resistance at terminal velocity drag force=m*g vt^2=m*g/cd so we will get terminal velocity vt now by applying work energy theorem work done by air resistance =change in energy =m*g*302-m*vt*vt/2 hope this will help u...

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