During a neighborhood baseball game in a vacant lot, a particularly wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 144-g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 10.9 m/s, shatters the glass as it passes through, and leaves the window at 8.01 m/s with no change of direction. Calculate the magnitude of this impulse (a positive number). The ball is in contact with the glass for 10.2 ms as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).

Magnitude of impulse: ___?___ N-s
Magnitude of F(avg): ___?___N

Explanation / Answer

J = m ( v2 - v1 )

J = 0.144 ( 8.01 - 10.9 ) = 0.41616 N .s <-----impulse

F . dt = J ;

F = J / t   

F = 0.41616 / [ 10.2 e -3 ]

F = 40.8 N <---------F avg   

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.