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<p>The model airplane in figure below is flying at a speed of&#160;<span style=\

ID: 1967790 • Letter: #

Question

<p>The model airplane in figure below is flying at a speed of&#160;<span>21</span>&#160;m/s on a horizontal circle of radius&#160;<span>17</span>&#160;m. The mass of the plane is&#160;<span>0.97</span>&#160;kg. The person holding the guideline pulls it in until the radius becomes&#160;<span>13</span>&#160;m. The plane speeds up, and the tension in the guideline becomes four times greater. What is the net work done on the plane?&#160;</p>

Explanation / Answer

net work done =change in kinetic energy v1=21 now initial tension=m*v*v/r =.97*21*21/17 =25.16 now final tension=4*25.16 =100.65 so new velocity v1 100.65=.97*v1*v1/13 v1=36.72 now change in kinetic energy =m/2(36.72*36.72-25.16*25.16) =.97/2(1348.6-633.056) =347.05J

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