A beam of protons is accelerated easterly from rest through a potential differen

Question

A beam of protons is accelerated easterly from rest through a potential difference of 2.0 kV . It enters a region where there exists an upward pointing uniform electric field. This field is created by two parallel plates separated by 20cm with a potential difference of 250V across them.
What is the speed of the protons as they enter the electric field?
Express your answer using two significant figures.
= m/s




Part B
Find the magnitude of the magnetic field (perpendicular to ) needed so the beam passes undeflected through the plates.
Express your answer using two significant figures.
= mT




Part C
What is the direction of this magnetic field?
toward the north
toward the south


Part D
What happens to the protons if the magnetic field is greater than the value found in part B?
the protons will be deflected downward
the protons will be deflected upward

Explanation / Answer

protons, m = 1.67*10-27 kg, q = 1.6*10-19 C, V1 = 2.0 kV, d = 20 cm, V2 = 250 V,
What is the speed of the protons as they enter the electric field?
mv2 = qV1, so v = (2qV1/m) = 6.19*105 m/s

Part B
Find the magnitude of the magnetic field (perpendicular to ) needed so the beam passes undeflected through the plates.
E = V2/d = 1250 V/m
B = E/v = 2.03 mT

Part C
What is the direction of this magnetic field?
toward the north


Part D
What happens to the protons if the magnetic field is greater than the value found in part B?
the protons will be deflected downward

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