A beam of light is directed at a linear polarizing filter that has a transmissio

Question

A beam of light is directed at a linear polarizing filter that has a transmission direction of 45° relative to the x-axis. 1) In which case is the fraction of the original light intensity reduced to a minimum? Case 1: Incident light is polarized parallel to the x-axis. Case 2: Incident light is polarized at-45° relative to the x-axis. Case 3: Incident light is unpolarized Submit You currently have 0 submissions for this question. Only 2 submission are allowed. You can make 2 more submissions for this question. (Survey Question) 2) Briefly explain your answer to the previous question. Submit You currently have 0 submissions for this question. Only 2 submission are allowed. You can make 2 more submissions for this question. 3) Unpolarized light is directed at three pairs of linear polarizing filters. The intensity of light directed at each pair is the same. Which pair transmits the minimum intensity of light? First polarizing filter Second polarizing filter Pair 1 Transmission axis parallel to the Transmission axis at 30 with vertical direction respect to the vertical direction Transmission axis at 45° with respect to the vertical direction Transmission axis at 45o with respect to the vertical direction Pair 2 Transmission axis at 30° with respect to the vertical direction Transmission axis at-600 with respect to the vertical direction Pair 3 Pair 1 Pair 2 Pair 3 Submit You currently have 0 submissions for this question. Only 2 submission are allowed. You can make 2 more submissions for this question. Survey Question) 4) Briefly explain your answer to the previous question. Submit You currently have 0 submissions for this question. Only 2 submission are allowed. You can make 2 more submissions for this question.

Explanation / Answer

(1)
Correct option :- (Case 2)
(2)
Using Malus Law,
I = Io * cos^()
Where is the angle btw the transmission direction of two polarizing filter !!
So,
If initial light is polarized w.r.t - 45o , then = 90o for second filter !!
I = Io * cos^(90)
I = 0

(3)
Let the initial intensity be Io.

1st pair,
I1 = Io/2
I2 = Io/2 * cos^2(30)
I2 = 0.375 * Io

2nd pair,
I1 = Io * cos^2(45) = Io/2
I2 = Io/2 * cos^2(0)
I2 = 0.5 * Io

3rd pair,
I1 = Io * cos^2(30) = 0.75 *Io
I2 = 0.75 *Io * cos^2(90)
I2 = 0

Correct option :-(3)

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