A ladder with a length of 12.8 m and weight of 509.0 N rests against a frictionl

Question

A ladder with a length of 12.8 m and weight
of 509.0 N rests against a frictionless wall,
making an angle of 56.0degrees with the horizontal.

a)What is the horizontal force exerted on the
base of the ladder by Earth when a firefighter
weighing 759.0 N is 2.29 m from the bottom
of the ladder.
Answer in units of N

b)Find the vertical force exerted on the base of
the ladder by Earth.
Answer in units of N
c)If the ladder is just on the verge of slipping
when the firefighter is 7.53 m up, what is the
coefficient of static friction between the ladder
and the ground?

Explanation / Answer

let ' f ' be the horizontal force applied by the wall on the ladder applying moment equilibrium about the point of contact of the ladder with the earth f*12.8*sin56 = 509*6.4*cos56 + 759*2.29*cos56 f = 263.25 N balancing forces along horizontal direction we get horizontal force applied by the earth = f so,the horizontal force applied the earth on the ladder = 263.25 N

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