Calculate the Angular Velocity and the Angular Acceleration of the hands of a cl

Question

Calculate the Angular Velocity and the Angular Acceleration of the hands of a clock in rads/sec

Seconds hand:
Minutes hand:
Hour hand:


I know that the angular velocity is change in theta divided by change in time. When I calculate seconds hand I take 2*Pi/60 because it takes 60 seconds to make a full rotation on the clock and I get .105 rad/s and then I divide this angular velocity over the change in time .105/60 and I get .00175 for angular acceleration, but my answers keep getting sent back as wrong. Please help! Thanks

Explanation / Answer

They are asking you for to find the angular velocity. The formula you will be using is 2*pi/seconds a.) the second hand 2*pi/60 seconds (becaus there are 60 seconds in a minute) = .1047197551 rad/s b.) the minute hand 2*pi/3600 seconds (because i had to multiply 60*60 to see how many seconds were in 60 minutes) =0.0017453293 rad/s c.) the hour hand 2*pi/43200 (becaue there are 12 hours and there are 60 minutes in an hour so i converted to minutes which was 60*60=720; and then i had to multiply 720*60=43200 to give the seconds in 12 hours) to find the angular acceleration d.) the acceleration is constant on a clock that is working properly so the acceleration will be 0 because its not slowing down or speeding up its the same I hope this will help you out...

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