A barefoot field-goal kicker imparts a speed of 29 m/s to a football initially a
ID: 1976287 • Letter: A
Question
A barefoot field-goal kicker imparts a speedof 29 m/s to a football initially at rest.
If the football has a mass of 0.78 kg and the
time of contact with the ball is 0.02 s, what
is the force exerted by the ball on the kicker’s
foot?
Answer in units of N
A(n) 0.51 kg softball is pitched at a speed of
11 m/s. The batter hits it back directly at the
pitcher at a speed of 21 m/s. The bat acts on
the ball for 0.019 s.
What is the magnitude of the average force
exerted by the bat on the ball during contact?
Two shuffleboard disks of equal mass, one
orange and the other yellow, are involved in
an elastic collision. The yellow disk is initially
at rest and is struck by the orange diskmoving
initially to the right at 6.99 m/s. After the
collision, the orange disk is at rest.
What is the velocity of the yellow disk after
the collision?
Answer in units of m/s
Explanation / Answer
we have the equation of motion as v = u+at here u=0 thus v = at or a = v/t = 29m/s /0.02s = 1450 m/s^2 the force exerted by the ball on the kicker’s footis F = ma = ma here m = 0.78 kg calculate for F F= 0.78* 1450 m/s^2= 1131 kg m/s^2
therefore F = 1131 N.
please post each question separately. thank you. we have the equation of motion as v = u+at here u=0 thus v = at or a = v/t = 29m/s /0.02s = 1450 m/s^2 the force exerted by the ball on the kicker’s footis F = ma = ma here m = 0.78 kg calculate for F F= 0.78* 1450 m/s^2
= 1131 kg m/s^2
therefore F = 1131 N.
please post each question separately. thank you. we have the equation of motion as v = u+at here u=0 thus v = at or a = v/t = 29m/s /0.02s = 1450 m/s^2 the force exerted by the ball on the kicker’s footis F = ma = ma here m = 0.78 kg calculate for F F= 0.78* 1450 m/s^2
= 1131 kg m/s^2
therefore F = 1131 N.
please post each question separately. thank you.
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