A cart loaded with bricks has a total mass of 11 kg and is pulled at constant sp

Question

A cart loaded with bricks has a total mass
of 11 kg and is pulled at constant speed by
a rope. The rope is inclined at 20.3 above
the horizontal and the cart moves 10.8 m on
a horizontal floor. The coefficient of kinetic
friction between ground and cart is 0.8 .
The acceleration of gravity is 9.8 m/s2 .

The Normal force exerted on the cart by the floor is 83.18357 N

.7187060448 kJ work is done on the cart by the rope.

Note: The energy change due to friction is a
loss of energy.

What is the energy change Wf due to friction? in units of kJ

Explanation / Answer

Mass of the cart m = 11 kg

Inclination of the rope ? = 20.3 deg

Dispalcement of the cart x = 10.8 m

Coefficient of friction µ = 0.8

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Frictional force f = µN

here the normal force N = mg - Tsin? = 83.18357 N

Therefore the work done by fricitional force is

                             Wf = f*x = (0.8) (83.18357 N) (10.8 m)

                                          = 718.7 J or 0.7187 kJ

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