One end of a meter stick is pinned to a table, so the stick can rotate freely in

Question

One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the table top. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. One force has a magnitude of 2.00 N and is applied perpendicular to the stick at the free end. The other force has a magnitude of 6.00 N and acts at a 30.0 degrees angle with respect to the stick. Where along the stick is the 6.00-N applied? Express this distance with respect to the end that is pinned.

Explanation / Answer

given this, just solve as 6.00sin(30.6)*x - 2.00*1 = 0 x = 0.655 m

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