#6!!! Help please A 61-kg man standing on a scale in an elevator notes that as t
ID: 1997546 • Letter: #
Question
#6!!! Help please A 61-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 830 N. What Is the acceleration of the elevator? m/s^2 upward Click ·'start' in the following Active Figure depicting static and kinetic frictional forces with a given applied force to a trash can to complete the exercise. A trash can with a mass of 11 kg has a coefficient of static friction of mu = 0.88 and a coefficient of kinetic friction of mu_k = 0.34. (The Active Figure applies to a similar situation, but the values of the mass, coefficient of static friction and coefficient of kinetic friction may be different. So the values it gives may not be the same values you obtain from your calculations.) What Is the maximum horizontal force i that can be exerted without moving the trash can? Suppose this force is just barely exceeded. Determine the acceleration of the trash can as it moves. The trash can is being pushed near its base but the applied force is balanced by the force of static friction. The maximum force of static friction Is determined by the coefficient of static friction and the normal force that the ground exerts on the trash can.Explanation / Answer
Here ,
6)
m =61 Kg
F = 830 N
let the acceleration is a
as F = m * (g + a)
830 = 61 * (9.8 + a)
a = 3.81 m/s^2
the acceleration is 3.81 m/s^2
7)
m = 11 Kg
us = 0.88
uk = 0.34
a) maximum horizontal force = us * m * g
maximum horizontal force = 0.88 * 11 * 9.8
maximum horizontal force = 94.9 N
b)
let the acceleration is a
94.9 - 0.34 * 9.8 * 11 = 11 * a
a = 5.292 m/s^2
the acceleration of trash can is 5.292 m/s^2
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