Two small beads having positive charges 3q and q are fixed at the opposite ends

Question

Two small beads having positive charges 3q and q are fixed at the opposite ends of a horizontal, insulating rod, extending from the origin to the point x = d. A third small charged bead is free to slide on the rod. Say the equilibrium position of the small free bead is given by k. If the charge on this third free bead is doubled, what happens to its equilibrium position?

a. the equilibrium position shifts left to k/4 b. the equilibrium position remains at k c. the equilibrium position shifts right to 5k/2 d. the equilibirum position shifts left to k/2 e. the equilibrium position shifts right to 5k/4

Explanation / Answer

b. the equilibrium position remains at k

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.