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Humid air breaks electrically down when its molecules become ionized. This happe

ID: 2004157 • Letter: H

Question

Humid air breaks electrically down when its molecules become ionized. This happens in an electric field |E| = 3.11 x 106 N/C. In that field, calculate the magnitude of the electrostatic force on an ion with a double positive charge.
Express the result in unit [N] to three significant figures. If you must use scientific notation, please enter as follows: ex. 0.00012 = 1.2E-4. Only answer in numerical values, no units. For negative numbers, leave no space between the negative sign and the number (right: -1.00, wrong, - 1.00).

Explanation / Answer

electriv field E = 3.11*106 N/C positive charge: the deficiency of electrons on a body or particle is known as positive charge. positive charge: the deficiency of electrons on a body or particle is known as positive charge. for doubly ionized atom :        charge = chrge of two protons             q = (2)(1.6*10-19 C)                = 3.2*10-19 C                = 3.2*10-19 C the relation betweev electrostatic force and electric field is                                Fe = Eq   ........ (1) substitute the given data in eq (1), we get            Fe = (3.11*106 N/C)(3.2*10-19 C)                 = 9.952*10-13 N
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