After class, a physics student walks a distance of 22.3 meters in a direction of

Question

After class, a physics student walks a distance of 22.3 meters in a direction of 40 degrees north of east in 29.4 seconds. The student then walks a distance of 33.6 meters in a direction 15 degrees west of north in 40.2 seconds. The student then walks a distance of 28 meters in a direction of 38 degrees west of south in 30.2 seconds. finally, the student turns and walks a distance of 25.1 meters in a direction of 22 degrees south of east in 30.3 seconds. What is the final displacement of the student from the starting point?

Explanation / Answer

Average speed is a scalar quantity so direction is not needed. It equals the sum of all the distances divided by the times, divided by the number of distance/times. [(22.3/29.4)+(33.6/40.2)+(28/30.2)+(25.1/30.3)]/4 = (.759+.836+.927+.828)/4 = .8375m/s

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