<p>A resistor R is placed in parallel with another resistor 2R. The combination

Question

<p>A resistor R is placed in parallel with another resistor 2R. The combination is placed in a series with an inductor L and a DC battery with voltage E. The total current leaving the battery at the moment the circuit is closed is.</p>
<p>a) E/2R</p>
<p>b) E/R</p>
<p>c) 3E/2R</p>
<p>d) zero</p>
<p>In the situatin above the current settles down and the inductor acts like a short; there would be just two resistors in parallel with the battery. Try to figure the current in this case.</p>

Explanation / Answer

   A resistor R is connected parallel with another resistor of value 2R Thus, resultant resistence of them is :    R ' = R (2R) / ( R + 2R )          = 2R2 / 3 R          = 2R / 3 DC battery voltage = E Thus, total current leaving at the moment when the circuit is closed is : current : I = E / R'                   = E / (2R / 3)                   = 3E / 2R Note : The action of component L not effected                 when at the moment of circuit is closed    so, current : I = 3E / 2R Thus, among the given :     option :    C is correct Thus, among the given :     option :    C is correct

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