A 30 Ohm resistor and a 250 mu F capacitor are placed in series with an AC volta

Question

A 30 Ohm resistor and a 250 mu F capacitor are placed in series with an AC voltage source of maximum voltage 50 V and angular frequency100 rad/s. Determine the capacitive reactance of the circuit Determine the impedance of the circuit Determine the maximum current that flows in the circuit To the right is a graph of the current m the circuit as a function of tune for just the first half period. On the same graph, sketch a qualitatively coned graph of the voltage across the capacitor as a function of tune Now an inductor is added in series with the resistor and capacitor Would you expect the impedance of the circuit to go up or down? Explain your reasoning.

Explanation / Answer

Resistence = R = 30 capacitence = C = 250 x10-6 F Maximum Voltage = V max = 50 V Angualr frquency = w = 100 rad/s (a) Capacitive reactence : X c = 1/ w C          = 1/ (100)(250 x10-6)          = 1/250 x 10-3             = 4 (b)    Impedence of the circuit is the total rsistence offred    by the circuit .    Z   = [ R2 + (1/ w C )2 ]         = [ (30)2 + 42 ]          = 30.265 (c )    Maximum current flows throug the circuit is ;              I max = V max / Z                        =   50 / 30.265                        = 1.652 A Please post remaining seperately..,

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