Different isotopes of the same element emit light at slightly different waveleng

Question

Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a hydrogen atom is 656.45 nm; for deuterium, the corresponding wavelength is 656.27 nm.
Note: I already got a) and d). But I don't know to get b) and c).
a) What minimum number of slits is required to resolve these two wavelengths in second order?
b) If the grating has 500.00 slits/mm, find the angle of the wavelength of 656.45 nm in the second order.
Express your answer using six significant figures.
c) If the grating has 500.00 slits/mm, find the angle of the wavelength of 656.27 nm in the second order.
Express your answer using six significant figures.

Explanation / Answer

d sin (theta m) = m lamda d is spacing, we have 1/spacing m is order, we have second order sin (theta 2) = 2 lamda / d d = mm/500 = microns/.5 = 2 microns part b) lamda = 0.65645 microns sin theta 2 = 2*0.65645/2 = 0.65645 theta 2 = 41.0297 deg part c) lamda = 0.65627 microns theta 2 = 41.0160 deg

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.