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Link to question with available attempts. me axis. Disk A has a moment of inerti

ID: 2029570 • Letter: L

Question

Link to question with available attempts. me axis. Disk A has a moment of inertia of 9.70 kg-m2 and an angular velocity of +2.54 rad/s. Disk B is rotating with an angular velocity of -6.78 rad/s. The two disks are then linked together without the aid of any external torques, so that they rotate as a single unit with an angular velocity of -3.64 rad/s. The axis of rotation for this unit is the same as that for the separate disks. What is the moment of inertia of disk B? Number the tolerance is +/-296 Click if you would like to Show Work for this question Units Open Show Work LINK TO TEXT

Explanation / Answer

Here ,

I1 = 9.70 Kg.m^2

w1 = 2.54 rad/s

I2 = ?

w2 = - 6.78 rad/s

I = - 3.64 rad/s

Using conservation of angular momentum

I1 * w1 + I2 * w2 = (I1 + I2) * wf

9.70 * 2.54 - I2 * 6.78 = (9.70 + I2) * (-3.54)

solving for I2

I2 = 18.2 Kg.m^2

the moment of inertia is 18.2 Kg.m^2

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