The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I1-1.18 A out of the page and the current in the outer conductor is I2-2.90 A into the page. Assuming the distance d = 1.00 mm, answer the following. (a) Determine the magnitude and direction of the magnetic field at pointa magnitude direction-Select- HT (b) Determine the magnitude and direction of the magnetic field at point b. magnitude directionSelect

Explanation / Answer

A.

Inet = i1 = 1.18 A

r = d = 1.00 mm

B = ?Inet / 2?r = 2 * 10-7 * 1.18 / 0.001 = 2.36 * 10^-4 T = 236?T, pointing upward

b)

Inet = i2 - i1 = 2.90 - 1.18 = 1.72 A

r = 2*d = 2.00 mm

B = ?inet / 2?r = 2 * 10-7 * 1.72 / 0.002 = 1.72 * 10-4 T = 172 muT, pointing downward

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.