An electron is accelerated from rest by a potential difference of 350 V. It then

Question

An electron is accelerated from rest by a potential difference of 350 V. It then enters a uniform magnetic field of magnitude 200 mT with its velocity perpendicular to the field (a) Calculate the speed of the electron. m/s (b) Calculate the radius of its path in the magnetic field lMath Help Right-hand Rule- Velocity-Field-Force My Notes Ask Your A 13.0 g wire of length L- 53.0 cm is suspended by a pair of flexible leads in a magnetic field of 0.310 T, what is the magnitude and direction of the current required to remove the tension in the supporting leads? (Take right to be positive.) Math Help Cross product- Magnitude & Angle The bent wire shown in the figure below lies in a uniform magnetic field. Each straight section is 2.4 m long and makes an angle of ? 60° with the x axis, and the wire carries a current of 2.0 A. (a) What is the net magnetic force on the wire in unit-vector notation if the magnetic field is 4.0T? magnitude N direction (b) What is the net magnetic force on the wire in unit-vector notation if the magnetic field is 4.0i T? magnitude N direction

Explanation / Answer

Many problems.

I am solving the first one as per guideline.

(a) Potential energy drop of the electron = qV

This must be equal to the kinetic energy gained = 1/2 mv^2

Solve for the speed of the electron:

v = sqrt (2qV/m)

put the values -

v = sqrt[(2x1.6x10^-19x350) / (9.109 x 10^-31)] = 11.09 x 10^6 m/s

(b) Again, we have the centrifugal force = mv^2 / r

and this must be equal to the magnetic force = qvB

So the radius is:
r = mv / qB
= sqrt (2Vm/qB) = sqrt[(2*350*9.109*10^-31) / (1.6*10^-19*0.2)] = 141.16 x 10^10^-6 m

= 1.4116 x 10^-4 m

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