(1890) Problem 4: The electric field in a certain region is given by the functio
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(1890) Problem 4: The electric field in a certain region is given by the function: E- Akcos(hx)cos(by)i - Absin(bx)sin(by)j where A-16 N m/C, k- 0.25 m, and b-1.15 m. The points in the figure are given by values xi-1.5 m and yi 2.5 m. (0,0) (x,0) Otheexpertta.com ? 14% Part (a) Enter an expression for the change in electric potential from point (0,0) to point (n,0) in terms ofA, b, and xi ? 14% Part (b) Enter an expression for the change in potential from point (x1,0) to point (xIJ) in terms ofA, k, b, xi and yi 14% Part (c) Enter an expression for the change in potential from pont (0,0) to point (nJi) along the path that passes through (x1,0) 14% Part (d) Enter an expression for the change in electric potential from point (0,0) to point (0, y) in terms of4, k, b. andy! 14% Part (e) Enter an expression for the change in electric potential from point (OJ) to point (ny) in terms ofAk, b, xi and yi -? 14% Part (f) Enter an expression for the change in potential from point (0,0) to point (xIJ), along the path that passes through (0,VI) 14% Part (g) Calculate the change in potential between (0,0) and (xly), in Joules, along the path that passes through (OJ) Grade Summa Deductions ry 0%Explanation / Answer
(a) E = (Akcos(kx1) - Ak) i
(b) E = Ak cos(kx1)(cos(by1-1) i - Absin(bx1)sin(by1) j
(c) E = Ak(cos(kx1cos(by1) - 1) i - Absin(bx1)sin(by1) j
(d) E = Akcos(by1) i - Ak j
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