Calculate the average pressure that a 320-N chair exerts on the floor by each of

Question

Calculate the average pressure that a 320-N chair exerts on the floor by each of its four legs if the cross-sectional area of each leg is 10. cm2.

a. 100 kPa

b. 62 kPa

c. 80 kPa

d. 67 kPa

e. 73 kPa

Which of the following results about the pressure at a depth of 0.400 m below the surface of a liquid in an open container is correct? (Only the pressure due to the liquid is taken into account and weight density = 133,000 N/m3 for mercury and 9,800 N/m3 for water.)

a. 49,000 Pa in water

b. 73,200 Pa in mercury

c. 66,500 Pa in mercury

d. 3,920 Pa in water

e. 4,410 Pa in water

A 0.123-kg piece of metal is rolled to a square sheet that is 1.0 m on each side, and then spread over the same size (1.0 m by 1.0 m) table. What pressure would it exert on the square table? (Hint: g =9.80 m/s2)

a. 1.4 Pa

b. 1.3 Pa

c. 1.0 N/cm^2

d. 1.2 Pa

e. 1.1 Pa

Explanation / Answer

total area of 4 legs = 4*10 = 40cm2

So, average pressure exerted = 320/40 = 8N/cm2 = 80000N/m2 = c. 80 kPa

_

Pressure = weight of column having unit cross-sectional area / cross-sectional area

for mercury , it is 0.4*1*133000 / 1 = 53200 Pa in mercury

for water , it is 0.4*1*9800 / 1 = d. 3,920 Pa in water

_

pressure it would exert on the square table = weight / area = 0.123*9.8 / 1*1 = d. 1.2 Pa

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