Homework Assignment #24 Begin Date: 4/2/2018 4.0000 PM-Due Date: 4.9/2018 9.00 P

Question

Homework Assignment #24 Begin Date: 4/2/2018 4.0000 PM-Due Date: 4.9/2018 9.00 PM End Date (50%) Problem 2: Answer the followng about the figure 200 > 60 ? 120 V 60 ? 20 ? ? 50% Part (a) what is de electrK current (in A) supplied by the battery to the electe cucut when the swtch s open? Topem Grade Susmary Potential 100% . atan acotansnh Degrees Radis Tedback deductics per eedback 50% Part (b) what is the electic current (z A) supplied by de battery to the electne excust when the mich is closed, ? 8

Explanation / Answer

Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Using this Information:

Part A

when switch is open

In left wire 60 and 20 are in series, So

Rs1 = 60 + 20 = 80 ohm

In right wire 60 and 20 are in series, So

Rs2 = 60 + 20 = 80 ohm

Now Rs1 and Rs2 are in parallel, So

Req = 80*80/(80 + 80) = 40 ohm

V = ieq*Req

ieq = V/Req = 120/40 = 30 Amp

Part B

when switch is closed

In bottom loop 60 and 20 are in parallel, So

Rp1 = 60*20/(60 + 20) = 15 ohm

In upper loop 60 and 20 are in parallel, So

Rp2 = 60*20/(60 + 20) = 15 ohm

Now Rp1 and Rp2 are in series, So

Req = 15 + 15 = 30 ohm

V = ieq*Req

ieq = V/Req = 120/30 = 40 Amp

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