I dont\'t know why but on this one i keep getting it wrong and i don\'t know wha

Question

I dont't know why but on this one i keep getting it wrong and i don't know what i'm doing wrong. can you show steps by step in how tosolve thisso i'll be able to check to see exactly where i went wrong. I know the equation is F=qvB. But since i'm looking for speed (velocity) it would be v=F/qB

Question #1)
An electron in an electron beam experiences
a downward force of 4.0×10-14 N while trav-
eling in a magnetic field of 4.8 × 10-2 T west.
The charge on a proton is 1.60×10-19.
a) What is the magnitude of the velocity?
Answer in units of m/s

Explanation / Answer

the force experienced by the charge in a magnetic field is given by

F = qvB

And for the speed of the charge

v = F/Bq

= (4.0*10-14 N)/(1.6*10-19 C)(4.8*10-2 T)

= 5.2*106 m/s

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