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A stone is thrown upward from the edge of a cliff, reaches its maximum height, a

ID: 2047013 • Letter: A

Question

A stone is thrown upward from the edge of a cliff, reaches its maximum height, and then falls down into the valley below. A motion diagram for this situation is given , beginning the instant the stone leaves the thrower’s hand. Construct the corresponding motion graphs taking the acceleration due to gravity as 10 . Ignore air resistance. In all three motion graphs, the unit of time is in seconds and the unit of displacement is in meters. In plotting the points, round-off the coordinate values to the nearest integer.

I already have part A. I really need help in how to find the points I need to graph in part B and C. Please help me!!!


A stone is thrown upward from the edge of a cliff, reaches its maximum height, and then falls down into the valley below. A motion diagram for this situation is given , beginning the instant the stone leaves the thrower's hand. Construct the corresponding motion graphs taking the acceleration due to gravity as 10 . Ignore air resistance. In all three motion graphs, the unit of time is in seconds and the unit of displacement is in meters. In plotting the points, round-off the coordinate values to the nearest integer. a_y(t). I already have part A. I really need help in how to find the points I need to graph in part B and C. Please help me!!! v_y(t). C) Construct a graph corresponding to the stone's vertical acceleration, y(t). B) Construct a graph corresponding to the stone's vertical velocity, A) Construct a graph corresponding to the stone's vertical displacement,

Explanation / Answer

a = -10 v = -10t + C at t=2, v=0 0 = -10(2) + C C = 20 v = -10t + 20 y = -5t^2 + 20t motion graphs come from those 3 equations. :)

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