(a) When a projectile is launched horizontally from a rooftop at a speed of v0x,

Question

(a) When a projectile is launched horizontally from a rooftop at a speed of v0x, does its horizontal component ever change in the absence of air resistance?

(b) Can you calculate the horizontal distance D traveled after launch simply as D = v0xt, where t is the fall time of the projectile?

(c) In calculating the fall time, is the vertical part of the motion just like that of a ball dropped from rest?

Explain each of your answers.

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.6 m/s, hoping to land on the roof of an adjacent building. The horizontal distance between the two buildings is D, and the roof of the adjacent building is 1.7 m below the jumping off point. Find the maximum value for D.
___________ m

Explanation / Answer

Horizontal component will not change unless the velocity is so large that earth's curvature matters and the force of gravity is no longer perpendicular to Vx.. The time, t taken to fall 2.1 m vertically is given by 1.7= (1/2)x9.8xt^2 t = sqrt(3.4/9.8) = 0.589 s The horizontal distance that the criminal covers during this time = 4.3xt m = 3.29 m If D is less than this value the criminal will land on the adjacent roof. Maximum value for D = 3.29 m

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