A battery is connected in series with a 0.27-? resistor and an inductor, as show

Question

A battery is connected in series with a 0.27-? resistor and an inductor, as shown in the figure below. The switch is closed at t = 0. The time constant of the circuit is 0.22 s, and the maximum current in the circuit is 7.6 A.

(a) Find the emf of the battery. 2.052V correct

(b) Find the inductance of the circuit. 59.4mH correct

(c) Find the current in the circuit after one time constant has elapsed.

2.812A Incorrect: Your answer is incorrect.

(d) Find the voltage across the resistor after one time constant has elapsed.

Incorrect: Your answer is incorrect. Did you accidentally divide or take the inverse in your calculation? .75924V

(e) Find the voltage across the inductor after one time constant has elapsed.

Incorrect: Your answer is incorrect. 1.29276V

I cant figure out c,d, or e please help! Thank you!

Explanation / Answer

a)
V = iR

V = .27 x 7.6 =2.052 V

b)
time cons = L/R =.22
L = 59.4 mH

c) i = io (1- e^-1)

i = i0 x .67
i= 4.824 A


d)voltage = i x 4.824 = 1.30248 V


e)
across inductor = 2.052 - 1.30248 = .74952 V

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