An air puck of mass m1 = 0.24 kg is tied to a string and allowed to revolve in a

Question

An air puck of mass m1 = 0.24 kg is tied to a string and allowed to revolve in a circle of radius R = 1.0 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.3 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.

(a) What is the tension in the string?


12.74 N

(b) What is the horizontal force acting on the puck?


12.74 N

(c) What is the speed of the puck?

????

Explanation / Answer

For part C, the horizontal force is providing a centripetal force since the puck is moving in a circle.

The formula for centripetal force is Fc = mv2/r

So...

12.74 = (.24)(v2)/1

v = 7.29 m/s

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