Scientist want to place a 4200kg satelite in orbit around Mars. They plan to hav

Question

Scientist want to place a 4200kg satelite in orbit around Mars. They plan to have the satelite orbit a distance equal to 1.5 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: Mmars=6.4191x10^23kg rmars=3.397x10^6m G=6.67428x10-^11 N-m^2kg^2 What is the force of attraction between Mars and the satelite and what speed should the satelite have to be in a perfectly circular orbit? and how much time does it take the satelite to complete one revolution?

Explanation / Answer

mass of the satellite m = 4200 kg ,
Mmars=6.4191x10^23kg rmars=3.397x10^6m
G=6.67428x10-^11 N-m^2kg^2 , distance R = 1.5rmars+rmars = 2.5rmars
force of attraction
F = GMm/R^2
solving we get
F = 2493.32 N

speed   v = GM/R = 2.245 km/s

time period T = 2R/v = 23756.3 sec = 395.93 min = 6.598 hours

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