In an experiment designed to measure the strength of a uniform magnetic field pr

Question

In an experiment designed to measure the strength of a uniform magnetic field produced by a set coils, the electron are accelerated from rest through a potential difference of 350V, and the beam associated with the electrons is measured to have a radius of 7.5 cm. Assuming the magnetic field is perpendicular to the beam. What is the magnitude of the magnetic field?

Explanation / Answer

1) first lets calculate the speed of electrons change in kinetic energy = change in potential energy mv^2=q*V --> v=sqrt(qV/m)=sqrt(1.6e-19*350/9.1e-31)=7.84e6 m/sec 2) now from the equation for radius in magnetic field R=mv/qB --> B=mv/qR=9.1e-31*7.84e6/(1.6e-19*0.075)=5.94e-4 T

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