In an experiment designed to test the output levels of three different treatment

Question

In an experiment designed to test the output levels of three different treatments, the following results were obtained: test for any significant diference between the mean output levels of the three treatments. Use -05. = 42 S -19. nr-17. Set up the ANOVA table and Source of Variatior Treatments Sum Degrees Mean SquareF of Squares of Freedom (to 2 (to 2 decimals) (to 4 decimals) P-value decimals) 190 95 5.78 Error Total 420 16 The pvalue is ( between-01-.025, What is your conclusion Conclude not all treatment means are equa

Explanation / Answer

here degree of freedom for numerator and denominator are 2 and 14 ; therefore for given test statistic

p value =0.0148

please revert.

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