Two 60 ohm resistor are connected in parallel. This parallel arrangement is conn

Question

Two 60 ohm resistor are connected in parallel. This parallel arrangement is connected in series with a 30 ohm resistor. The combination is then placed across a 120 V battery
a) draw diagram of circuit b) What is equivalent resistance of parallel part of circuit? c) What single resistor could replace the 3 original resistors? d) what is current in the circuit? e) what is voltage drop across the 30 ohm resistor? f) what is voltage drop across the parallel portion of the circuit? g) what is current in each branch of the parallel part of the circuit?

Explanation / Answer

the resulatant of 60 and 60 ohms in parallel is 30ohm (ans b parallel part)

and since another 30 ohm is in series with it ,total resistance=30+30=60 ohm (ans c)

current=120/60=2 Amps (ans D)

voltage drop = current * resistance=2*30=60Volts (ans E)

voltage drop across parallel portion=120-voltage drop across 30 ohm=60V ans F

current divides in the inverse ratio of resistances hence current in each branch = 2*1/2=1Amp each (ANs G)

 

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