Flowering time was measured on individuals from a population (shown by genotype
ID: 206651 • Letter: F
Question
Flowering time was measured on individuals from a population (shown by genotype of the individual- each value represents one individual).
MM
110
160
156
148
139
Mm
200
225
193
189
176
mm
40
46
51
40
56
a. Calculate the additive and dominance effect for this locus. Describe the type of dominance this locus exhibits.
b. Calculate the additive and dominance variance due to this locus assuming p=0.4.
c. If the total phenotypic variance for this population is 5000, what is the heritability in the broad sense? What is the narrow sense heritability?
MM
110
160
156
148
139
Mm
200
225
193
189
176
mm
40
46
51
40
56
Explanation / Answer
a) Condition 1 MM= a= p2=110, Mm=d=2pq=200, mm= -a=q2=40, p=0.4, q=0.6 ,dominant genetic effect value taken for calculation= 0.25, additive genetic effect value for calculation=0.5.
MM =110/350=0.31, Mm=200/350=0.57, mm=40/350=0.11 same calculation for the other conditions.
b) VA = additive variance= (1-2p)2= [1- 2 (0.4)]2= [1-2 x0.16]=[1-0.32]= 0.68 answer.
VP= phenotypic variation=[1-2pq]= [1-2 x 0.6 x0.4]= [1-0.24]= 0.76 answer.
c) N=5000, heritability in broad sense= VG= VA+ VD= 0.68+0.76=1.44
heritability in broad sense= h2= VG/VP= 1.44/0.76=1.89 answer.
heritability in narrow sense=h2= VA/VP= 0.68/0.76=0.89 answer.
heritability in narrow sense=
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.