A 50 cm long hollow glass cylinder is open at both ends and is suspended in air.

Question

A 50 cm long hollow glass cylinder is open at both ends and is suspended in air. A source o sound that produces a pure frequency is placed close to one end of the tube. The frequency of the sound source is slowly increased from a very low value. The tube is first observed to resonate when the source frequency is 320 Hz.

i) Calculate the speed of the sound in the tube.

(ii) The frequency of the source is slowly increased until resonance occurs again FOR THE THIRD AND FIFTH TIME. Calculate the frequency at which this happens.

Explanation / Answer

Part i)

The formula for a pipe open at both ends is

fn = nv/2L

(320) = (1)(v)/(2)(.5)

v = 320 m/s

Part ii

f3 = (3)(320)/(2)(.5)

f3 = 960 Hz

f5 = (5)(320)/(2)(.5)

f5 = 1600 Hz

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