A 5.6-mm -diameter proton beam carries a total current of 1.1 mA . The current d

Question

A 5.6-mm -diameter proton beam carries a total current of 1.1 mA . The current density in the proton beam, which increases with distance from the center, is given by J=Jedge(r/R) , where R is the radius of the beam and Jedge is the current density at the edge.

A). How many protons per second are delivered by this proton beam? Express your answer using two significant figures.

N= ???? protons per second

B).

Determine the value of Jedge .

Express your answer to two significant figures and include the appropriate units.

Jedge= ???? units

Explanation / Answer

J=Jedge(r/R)

current density =current /area =1.1 mA/pi(2.8mm)2 = 0.044 x 10-3A/m2

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