A 5.3 g bullet leaves the muzzle of a rifle with a speed of 320 m/s. What force

Question

A 5.3 g bullet leaves the muzzle of a rifle with a speed of 320 m/s.  What force (assumed constant) is exerted on the bullet while it is traveling down the 0.77 m long barrel of the rifle?

A freight train has a mass of 1.9 times 107 kg. If the locomotive can exert a constant pull of 8.5 times 105 N, how long does it take to increase the speed of the train from rest to 90 km/h? A 5.3 g bullet leaves the muzzle of a rifle with a speed of 320 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.77 m long barrel of the rifle?

Explanation / Answer

F = ma

a = (v-u)/t

F = m * (v-u)/t

90 km/hr = 90 * 5/18 = 25 m/s

8.5 * 10^5 = 1.9 * 10^7 * ( 25-0) / t

t = 558.82 seconds

2) a=v^2/2x= 66493.5

F= ma= 5.3 * 10^-3 * 66493.5 = 352.4 N

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