(f the last three digits in Banner ID are \"123 then you would have L 42.12 cm.e
ID: 2077243 • Letter: #
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(f the last three digits in Banner ID are "123 then you would have L 42.12 cm.etc) 1 (8 pts). Calculate the volume and mass of the plastic at 20.0 C 2 (8 pts). The block is placed in the Atlantic ocean. Determine if the block floats. If the block sinks. calculate the force the bottom ofthe ocean exerts on the block. If the block floats, how much of the block's height is submerged? 3 (8 pts). Continuing with the previous question. f the block sinks, determine the density of the block necessary for the block to float with at most 90% of the block submerged. If the block floats.determine how much mass can be added before the block will sink. Problems 4 through 6 in this section deal with the same situation involving a sheet of charge: 2rrkqA, where k electric constant, q- total charge on the sheet, and A total area of the sheet. (8 pts). A sheet of charge has a total charge of -15.2 uc spread over an area of 17Acm (yy 1ast two digits of your Banner ID; if last three Banner ID digits are 789, use "89") A charge Q -6.yy uc is placed 3.64 cm (ocation A) from a single sheet of charge. Determine the electric field at two locations: A. a distance of 3.64 cm and B, a distance of sheet of charge. Sketch the electric field, making sure to show the locations of A and B. 5 (8 pts). a) Determine the force experienced by Q at each location,A and B. b) If allowed to move, will from B or from B to A? A to B or B to A c) Will the acceleration Q experiences be constant while it moves from 6 (8 pts). a) Determine how much work the electric force does between the locations A and B. b) If Q from A to B, what form of energy will Qhave? c) Will the energy form be the same if Q moves from B to A? If not, what form will it have?Explanation / Answer
charge on the sheet q = -15.2 e-6 C
area of the sheet A = 17.4 cm2
Electric field form the sheet Esh = 2k*pi*q/A = 2*9.0e+9*3.14*-15.2e-6/17.4e-4 = -49.4 e+7 N/C
charge Q = -6.00e-6 C
Force on the charge F = QE = -6.00e-6*49.4e+7 = +2964 N
The electric field is indepeden of the distance and is const and A and B , the force is same at A and B
b) the force is away from the sheet , the charge will move from A to B
c) as the froce is const. the acceleration is const.
6. a) work done W = F.s = 2964(18.3-3.64)/100 = 434.52 J
b) Q moves from Higher pot to lower pot. It will gain KE energy
c) when Q moves from B to A it will gain Potential energy.
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